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3.Multiply the rst row by so that the **pivot** is 1. 4.Add multiples of the rst row to each other row so that the rst entry of every other row is zero. 5.Now ignore the rst row and rst column and repeat steps 1-5 until the matrix is in RREF. Example 3x 3 = 9 x 1 +5x 2 2x 3 = 2 1 3 x 1 +2x 2 = 3 First we write the system as an augmented matrix: 1.

- We build the
**Simplex Tableau**and solve the problem. We take the minimum of the negative from z j - c j = -3, it occurs at x 2, so entering variable is 2, s=2. Now we calculate the **The**following**tableau**is a restatement of the starting**tableau**with its**pivot**TOW and column highlighted. The Gauss-Jordan computations needed to produce the new basic solution include two types. 1.**Pivot**row a. Replace the leaving variable in the Basic column with the entering variable. b. New**pivot**row = Current**pivot**row +**Pivot**element 2.- 6.6.45 (lecture 18): use the method in Lecture 18 to
**find**an initial bfs. 6.6.50 (lecture 17): use the network**simplex**method from class. For an initial BFS, take the optimal solution given on page 216, modified so that x 15 is nonbasic at its upper bound, and x 45 is basic. Note that just one edge has a capacity constraint, so this is the only ... - The solution (+
**tableau**steps): In the first Table the**pivot**column is chosen correctly.. i.e - the most negative column in the last row (the objective function). However as you can see leading **The****pivot**is**The****pivot**is located in row column. This problem has been solved! See the answer Show transcribed image text Expert Answer 100% (1 rating) To**find****pivot**column, we**find****the**most negative number in the given**simplex****tableau**. To**find****pivot**row, we divide the last column with the piv View the full answer